Probability One

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 1674		Accepted: 1151

Description

Number guessing is a popular game between elementary-school kids. Teachers encourage pupils to play the game as it enhances their arithmetic skills, logical thinking, and following-up simple procedures. We think that, most probably, you too will master in few minutes. Here’s one example of how you too can play this game: Ask a friend to think of a number, let’s call it n

₀. Then: 

2. Ask your friend to compute n₁ = 3 * n₀ and to tell you if n₁ is even or odd.
3. If n₁ is even, ask your friend to compute n₂ = n₁/2. If, otherwise, n₁ was odd then let your friend compute n₂ = (n₁ + 1)/2.
4. Now ask your friend to calculate n₃ = 3 * n₂.
5. Ask your friend to tell tell you the result of n₄ = n₃/9. (n₄ is the quotient of the division operation. In computer lingo, ’/’ is the integer-division operator.)
6. Now you can simply reveal the original number by calculating n₀ = 2 * n₄ if n₁ was even, or n₀ = 2 * n₄ + 1 otherwise.

Here’s an example that you can follow: If n

₀ = 37, then n

₁ = 111 which is odd. Now we can calculate n

₂ = 56, n

₃ = 168, and n

₄ = 18, which is what your friend will tell you. Doing the calculation 2 * n

₄ + 1 = 37 reveals n

₀.

Input

Your program will be tested on one or more test cases. Each test case is made of a single positive number (0 < n

₀ < 1,000,000). 

The last line of the input file has a single zero (which is not part of the test cases.)

Output

For each test case, print the following line: 

k. B Q 

Where k is the test case number (starting at one,) B is either ’even’ or ’odd’ (without the quotes) depending on your friend’s answer in step 1. Q is your friend’s answer to step 4.

Sample Input

37380

Sample Output

1. odd 182. even 19

把整个过程换算完了就是把原数除以2。

代码：

#include 
    
     #include 
     
      #include 
      
       #include 
       
        #include 
        
         #include 
         
          using namespace std;int main(){ int num,i=1; while(cin>>num) { if(num==0) break; cout<
          <<". "; i++; if(num%2) cout<<"odd "; else cout<<"even "; cout<
         
        
       
      
     
    

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